5n^2-14=3n

Solution for 5n^2-14=3n equation:

5n^2-14=3n

We move all terms to the left:

5n^2-14-(3n)=0

a = 5; b = -3; c = -14;
Δ = b2-4ac
Δ = -32-4·5·(-14)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-17}{2*5}=\frac{-14}{10}
=-1+2/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+17}{2*5}=\frac{20}{10}
=2
$